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4
2016 Chandigarh RMO (4cos^2 9^o - 3) (4 cos^2 27^o -3) = tan 9^o
2016 Chandigarh RMO (4cos^2 9^o - 3) (4 cos^2 27^o -3) = tan 9^o
Source:
August 9, 2019
trigonometry
Problem Statement
Prove that
(
4
cos
2
9
o
–
3
)
(
4
cos
2
2
7
o
–
3
)
=
tan
9
o
(4\cos^29^o – 3) (4 \cos^227^o– 3) = \tan 9^o
(
4
cos
2
9
o
–3
)
(
4
cos
2
2
7
o
–3
)
=
tan
9
o
.
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