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I Soros Olympiad 1994-95 (Rus + Ukr)
11.1
2^{1995} > 5^{856} (I Soros Olympiad 1994-99 Round 2 11.1)
2^{1995} > 5^{856} (I Soros Olympiad 1994-99 Round 2 11.1)
Source:
May 26, 2024
algebra
inequalities
Problem Statement
Without using a calculator, prove that
2
1995
>
5
856
2^{1995} > 5^{856}
2
1995
>
5
856
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