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diophantine 2xy^2 + x + y + 1 = x^2 + 2y^2 + xy (HOMC 2015 J Q14)

Source:

August 6, 2019
Diophantine equationnumber theorydiophantine

Problem Statement

Determine all pairs of integers (x,y)(x, y) such that 2xy2+x+y+1=x2+2y2+xy2xy^2 + x + y + 1 = x^2 + 2y^2 + xy.