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n = 3t(n) + 5r(n), greatest odd divisor, smallest pos. divisor unequal to 1

Source: Dutch BxMO TST 2016 p1

August 24, 2019
number theorydivisoroddequation

Problem Statement

For a positive integer nn that is not a power of two, we de fine t(n)t(n) as the greatest odd divisor of nn and r(n)r(n) as the smallest positive odd divisor of nn unequal to 11. Determine all positive integers nn that are not a power of two and for which we have n=3t(n)+5r(n)n = 3t(n) + 5r(n).