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AM=KB wanted, AK =AO, KM =MC , KM //AC (2021 Kyiv City MO 8.4.1)

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February 16, 2021
geometryequal segments

Problem Statement

On the sides ABAB and BCBC of the triangle ABCABC, the points KK and MM are chosen so that KMACKM \parallel AC. The segments AMAM and KCKC intersect at the point OO. It is known that AK=AOAK =AO and KM=MCKM =MC. Prove that AM=KBAM=KB.