MathDB
ASU 405 All Soviet Union MO 1985 a_{2n}=a_n, a_{4n+1}=1, a_{4n+3}=0

Source:

August 5, 2019
periodicalSequence

Problem Statement

The sequence a1,a2,...,ak,...a_1, a_2, ... , a_k, ... is constructed according to the rules: a2n=an,a4n+1=1,a4n+3=0a_{2n} = a_n,a_{4n+1} = 1,a_{4n+3} = 0Prove that it is non-periodical sequence.