MathDB
Argentina Cono Sur TST 2012. Problem 5

Source:

April 26, 2015
geometryangle bisectorexcenter

Problem Statement

Let ABCABC be a triangle, and KK and LL be points on ABAB such that ACK=KCL=LCB\angle ACK = \angle KCL = \angle LCB. Let MM be a point in BCBC such that MKC=BKM\angle MKC = \angle BKM. If MLML is the angle bisector of KMB\angle KMB, find MLC\angle MLC.