MathDB
distance form circumcenter to orthocenter is AB+ AC when <A=120^o

Source: 2008 Oral Moscow Geometry Olympiad grades 10-11 p4

October 14, 2020
geometryorthocenterCircumcenterdistance

Problem Statement

Angle AA in triangle ABCABC is equal to 120o120^o. Prove that the distance from the center of the circumscribed circle to the orthocenter is equal to AB+ACAB + AC.
(V. Protasov)
Back to ProblemsView on AoPS