MathDB
angle BCM=angle DBA in a convex quad

Source: ItaMO 2010, p3

February 28, 2012
geometrypower of a pointradical axisgeometry proposed

Problem Statement

Let ABCDABCD be a convex quadrilateral. such that ∠CAB=∠CDA\angle CAB = \angle CDA and ∠BCA=∠ACD\angle BCA = \angle ACD. If MM be the midpoint of ABAB, prove that ∠BCM=∠DBA\angle BCM = \angle DBA.
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