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Poland - Second Round
1981 Poland - Second Round
3
f(f(x)) = - x continuous
f(f(x)) = - x continuous
Source: Polish MO Recond Round 1981 p3
September 9, 2024
algebra
continuous
functional
Problem Statement
Prove that there is no continuous function
f
:
R
→
R
f: \mathbb{R} \to \mathbb{R}
f
:
R
→
R
satisfying the condition
f
(
f
(
x
)
)
=
−
x
f(f(x)) = - x
f
(
f
(
x
))
=
−
x
for every
x
x
x
.
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