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min max of F =(y-x)(x+4y) when x^2y^2 + xy + 1 = 3y^2

Source: Czech-Polish-Slovak Junior Match 2014, Team p6 CPSJ

March 23, 2020
inequalitiesalgebraminimummaximumminmax

Problem Statement

Determine the largest and smallest fractions F=yxx+4yF = \frac{y-x}{x+4y} if the real numbers xx and yy satisfy the equation x2y2+xy+1=3y2x^2y^2 + xy + 1 = 3y^2.