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PA^2+PB^2+...+PH^2 =?, regular octagon ABC...H 1998 Portugal p2

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October 11, 2020
geometryRegularoctagon

Problem Statement

The regular octagon of the following figure is inscribed in a circle of radius 11 and PP is a arbitrary point of this circle. Calculate the value of PA2+PB2+...+PH2PA^2 + PB^2 +...+ PH^2. https://cdn.artofproblemsolving.com/attachments/4/c/85e8e48c45970556077ac09c843193959b0e5a.png
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