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AC = AA_1 if <ABC = 45^o, AA_1= _|_ CC_1 (2016 Kyiv City MO 9.5)

Source:

September 5, 2020
geometryequal segmentsperpendicularity

Problem Statement

On the sides BCBC and ABAB of the triangle ABCABC the points A1{{A} _ {1}} and C1{{C} _ {1}} are selected accordingly so that the segments AA1A {{A} _ {1}} and CC1C {{C} _ {1}} are equal and perpendicular. Prove that if ABC=45\angle ABC = 45 {} ^ \circ, then AC=AA1AC = A {{A} _ {1}} .
(Gogolev Andrew)