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Danube Competition in Mathematics
2009 Danube Mathematical Competition
1
Danube Mathematical Competition 2009
Danube Mathematical Competition 2009
Source:
July 15, 2012
Problem Statement
Let be
△
A
B
C
\triangle ABC
△
A
BC
.Let
A
′
A'
A
′
,
B
′
B'
B
′
,
C
′
C'
C
′
be the foot of perpendiculars from
A
A
A
,
B
B
B
and
C
C
C
respectively. The points
E
E
E
and
F
F
F
are on the sides
C
B
′
CB'
C
B
′
and
B
C
′
BC'
B
C
′
respectively, such that
B
′
E
⋅
C
′
F
=
B
F
⋅
C
E
B'E\cdot C'F = BF\cdot CE
B
′
E
⋅
C
′
F
=
BF
⋅
CE
. Show that
A
E
A
′
F
AEA'F
A
E
A
′
F
is cyclic.
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