Let A1,B1,C1 be the midpoints of the sides BC,CA,AB respectively of a triangle ABC. Points K on segment C1A1 and L on segment A1B1 are taken such that
KA1C1K=AC+ABBC+ACandLB1A1L=BC+ABAC+AB.If BK and CL meet at S, prove that ∠C1A1S=∠B1A1S.