MathDB
AB / BF - AC /AE = 1, parallelogram related

Source: 2004 Bosnia & Herzegovina JBMO TST p4

May 27, 2020
geometryparallelogramangle bisector

Problem Statement

Let ABCDABCD be a parallelogram. On the ray (DB(DB a point EE is given such that the ray (AB(AB is the angle bisector of ∠CAE\angle CAE. Let FF be the intersection of CECE and ABAB. Prove that ABBF−ACAE=1\frac{AB}{BF} - \frac{AC}{AE} = 1
Back to ProblemsView on AoPS