Time for an IMOTC party!
Source: India IMOTC 2024 Day 2 Problem 3
May 31, 2024
combinatoricsgraph theory
Problem Statement
At an IMOTC party, all people have pairwise distinct ages. Some pairs of people are friends and friendship is mutual. Call a person junior if they are younger than all their friends, and senior if they are older than all their friends. A person with no friends is both junior and senior. A sequence of pairwise distinct people is called photogenic if:
1. is junior,
2. is senior, and
3. and are friends, and is older than for all .Let be a positive integer such that for every photogenic sequence , is not divisible by . Prove that the people at the party can be partitioned into groups so that no two people in the same group are friends.Proposed by Shantanu Nene