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Time for an IMOTC party!

Source: India IMOTC 2024 Day 2 Problem 3

May 31, 2024
combinatoricsgraph theory

Problem Statement

At an IMOTC party, all people have pairwise distinct ages. Some pairs of people are friends and friendship is mutual. Call a person junior if they are younger than all their friends, and senior if they are older than all their friends. A person with no friends is both junior and senior. A sequence of pairwise distinct people A1,,AmA_1, \dots, A_m is called photogenic if: 1. A1A_1 is junior, 2. AmA_m is senior, and 3. AiA_i and Ai+1A_{i+1} are friends, and Ai+1A_{i+1} is older than AiA_i for all 1im11 \leq i \leq m-1.
Let kk be a positive integer such that for every photogenic sequence A1,,AmA_1, \dots, A_m, mm is not divisible by kk. Prove that the people at the party can be partitioned into kk groups so that no two people in the same group are friends.
Proposed by Shantanu Nene