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Tuymaada Olympiad
1997 Tuymaada Olympiad
2
system in N: 3x^2+6y^2+5z^2=1997, 3x+6y+5z=161
system in N: 3x^2+6y^2+5z^2=1997, 3x+6y+5z=161
Source: Tuymaada 1997 p2
April 28, 2019
algebra
system of equations
Natural Numbers
Diophantine Equations
Problem Statement
Solve in natural numbers the system of equations
3
x
2
+
6
y
2
+
5
z
2
=
1997
3x^2+6y^2+5z^2=1997
3
x
2
+
6
y
2
+
5
z
2
=
1997
and
3
x
+
6
y
+
5
z
=
161
3x+6y+5z=161
3
x
+
6
y
+
5
z
=
161
.
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