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diophantine 2^x - y^2 = 1 (HOMC 2017 J Q2)

Source:

August 7, 2019

number theorydiophantineDiophantine equation

Problem Statement

How many pairs of positive integers

(x, y)

are there, those satisfy the identity

2^x - y^2 = 1

?
(A):

1

(B):

2

(C):

3

(D):

4

(E): None of the above.

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