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x^2 - 2xy + 5y^2 + 2x - 6y - 3 = 0 diophantine (HOMC 2019 JI-11)
x^2 - 2xy + 5y^2 + 2x - 6y - 3 = 0 diophantine (HOMC 2019 JI-11)
Source:
November 7, 2020
number theory
diophantine
Diophantine equation
Problem Statement
Find all integers
x
x
x
and
y
y
y
satisfying the following equation
x
2
−
2
x
y
+
5
y
2
+
2
x
−
6
y
−
3
=
0
x^2 - 2xy + 5y^2 + 2x - 6y - 3 = 0
x
2
−
2
x
y
+
5
y
2
+
2
x
−
6
y
−
3
=
0
.
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