MathDB
<AQT= 90^o wanted, altitudes, circumcircle (2021 Kyiv City MO Round2 9.2)

Source:

February 14, 2021
geometrycircumcircleright angle

Problem Statement

In an acute triangle ABAB the heights BE BE and CFCF intersect at the orthocenter HH, and MM is the midpoint of BCBC. The line EFEF intersects the lines MHMH and BCBC at the points PP and TT , respectively. APAP intersects the cirumcscribed circle of ABC\vartriangle ABC for second time at the point QQ . Prove that AQT=90o\angle AQT= 90^o.
(Fedir Yudin)