MathDB
Putnam 1996 A5

Source:

June 4, 2014
Putnamfloor functioncollege contests

Problem Statement

Let pp be a prime greater than 33. Prove that p2i=12p3(pi). p^2\Big| \sum_{i=1}^{\left\lfloor\frac{2p}{3}\right\rfloor}\dbinom{p}{i}.