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Sequence of binomial coefficients

Source: 54 Polish MO 2003 Second Round - First Day Problem 1

April 21, 2018
number theorybinomial coefficientsPoland

Problem Statement

Prove that exists integer n>2003n > 2003 that in sequence (n0)\binom{n}{0}, (n1)\binom{n}{1}, (n2)\binom{n}{2}, ..., (n2003)\binom{n}{2003} each element is a divisor of all elements which are after him.