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(AN)(NC) =(CD)(BN) in a cyclic ABCD with (AD)=(BD)

Source: 2013 Dutch BxMO / EGMO TST p5

September 19, 2018
geometrycyclic quadrilateralProductincirclecircumcircle

Problem Statement

Let ABCDABCD be a cyclic quadrilateral for which AD=BD|AD| =|BD|. Let MM be the intersection of ACAC and BDBD. Let II be the incentre of BCM\triangle BCM. Let NN be the second intersection pointof ACAC and the circumscribed circle of BMI\triangle BMI. Prove that ANNC=CDBN|AN| \cdot |NC| = |CD | \cdot |BN|.