MathDB
2020 Team #11

Source:

October 24, 2023
geometryteam test

Problem Statement

ABC\vartriangle ABC is right with C=90o\angle C = 90^o. The internal angle bisectors of A\angle A and B\angle B meet at point DD, while the external angle bisectors of A\angle A and B\angle B meet at point EE. Suppose that AD=1AD = 1 and BD=2BD = 2. The value of DE2DE^2 can be expressed as x+yzx+y \sqrt{z} for integers xx, yy, and zz, where zz is greater than 11 and not divisible by the square of any prime. Compute 100x+10y+z100x + 10y + z. Note: For a generic triangle PQR\vartriangle PQR, if we let QQ' be the reflection of QQ over PP, then the external angle bisector of P\angle P is the line that contains the internal angle bisector of QPR\angle Q'PR.