MathDB
Circumcenter equidistant from two points

Source: Sharygin Geometry Olympiad Correspondence Round 2017 P-10 (Grade-8-10)

May 1, 2017
geometrycircumcircle

Problem Statement

Points KK and LL on the sides ABAB and BCBC of parallelogram ABCDABCD are such that AKD=CLD\angle AKD = \angle CLD. Prove that the circumcenter of triangle BKLBKL is equidistant from AA and CC. Proposed by I.I.Bogdanov