k^3 - 36k^2 + 51k - 97 is a multiple of 3^2008.
Source: VAIMO 2008, Problem 3
January 3, 2009
number theory unsolvednumber theory
Problem Statement
Prove there is an integer for which k^3 \minus{} 36 k^2 \plus{} 51 k \minus{} 97 is a multiple of
Source: VAIMO 2008, Problem 3