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ASU 452 All Soviet Union MO 1987 a+A=b+B=c+C=k => aB+bC+cA <=k^2

Source:

August 7, 2019
algebrainequalities

Problem Statement

The positive numbers a,b,c,A,B,Ca,b,c,A,B,C satisfy a condition a+A=b+B=c+C=ka + A = b + B = c + C = k Prove that aB+bC+cAk2aB + bC + cA \le k^2