MathDB
x^2+y^2+z^2 if x+y+z=13, xyz= 72, 1/x+1/y+1/z=3/4

Source: Finland 2014, Problem 1

September 1, 2019
algebrasystem of equations

Problem Statement

Determine the value of the expression x2+y2+z2x^2 + y^2 + z^2,
if x+y+z=13x + y + z = 13 , xyz=72xyz= 72 and 1x+1y+1z=34\frac1x + \frac1y + \frac1z = \frac34.