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Fermat point and properties

Source:

October 12, 2010
geometry theoremsgeometry

Problem Statement

Given a triangle ABCABC, three equilateral triangles AEB,BFCAEB, BFC, and CGACGA are constructed in the exterior of ABCABC. Prove that: (a)CE=AF=BG(a) CE = AF = BG; (b)CE,AF(b) CE, AF, and BGBG have a common point.
I could not find a separate topic for this question and I need one. http://en.wikipedia.org/wiki/Fermat_point of course.
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