MathDB
f(f(x) + y) = ax + 1/f (1/y) , when x,y >0

Source: 49th Austrian Mathematical Olympiad National Competition (Final Round, part 2) 31st May 2018 p1

May 25, 2019
algebrafunctional equation

Problem Statement

Let a0a \ne 0 be a real number. Find all functions f:R>0R>0f : R_{>0}\to R_{>0} with f(f(x)+y)=ax+1f(1y)f(f(x) + y) = ax + \frac{1}{f\left(\frac{1}{y}\right)} for all x,yR>0x, y \in R_{>0}.
(Proposed by Walther Janous)