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2
2017 Discrete Tiebreaker #2
2017 Discrete Tiebreaker #2
Source:
October 12, 2022
2017
Discrete Math Tiebreaker
Problem Statement
Find the remainder of
7
1010
+
8
2017
7^{1010}+8^{2017}
7
1010
+
8
2017
when divided by
57
57
57
.
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