MathDB
I 13

Source:

May 25, 2007
floor functionfunction

Problem Statement

Suppose that n≥2n \ge 2. Prove that ∑k=2n⌊n2k⌋=∑k=n+1n2⌊n2k⌋.\sum_{k=2}^{n}\left\lfloor \frac{n^{2}}{k}\right\rfloor = \sum_{k=n+1}^{n^{2}}\left\lfloor \frac{n^{2}}{k}\right\rfloor.
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