MathDB
A different kind of power mean inequality

Source: Miklós Schweitzer 2013, P9

July 12, 2014
inequalitiesfunctionreal analysisreal analysis unsolved

Problem Statement

Prove that there is a function f:(0,)(0,){f: (0,\infty) \rightarrow (0,\infty)} which is nowhere continuous and for all x,y(0,){x,y \in (0,\infty)} and any rational α{\alpha} we have f((xα+yα2)1α)(f(x)α+f(y)α2)1α. \displaystyle f\left( \left(\frac{x^\alpha+y^\alpha}{2}\right)^{\frac{1}{\alpha}}\right)\leq \left(\frac{f(x)^\alpha +f(y)^\alpha }{2}\right)^{\frac{1}{\alpha}}. Is there such a function if instead the above relation holds for every x,y(0,){x,y \in (0,\infty)} and for every irrational α?{\alpha}?
Proposed by Maksa Gyula and Zsolt Páles