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3
2016 Geometry Tiebreaker #3
2016 Geometry Tiebreaker #3
Source:
August 11, 2022
2016
Geometry Tiebreaker
Problem Statement
Let
H
H
H
be the orthocenter of triangle
A
B
C
ABC
A
BC
, and
D
D
D
be the foot of
A
A
A
onto
B
C
BC
BC
. Given that
D
B
=
3
DB=3
D
B
=
3
,
D
H
=
2
DH=2
DH
=
2
, and
D
C
=
6
DC=6
D
C
=
6
, calculate
H
A
HA
H
A
.
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