MathDB
Turkey NMO 2004 P.1, Easy Problem

Source:

December 11, 2010
geometryparallelogramtrapezoidrectangleangle bisectorgeometry proposed

Problem Statement

In a triangle ABC\triangle ABC withB>C\angle B>\angle C, the altitude, the angle bisector, and the median from AA intersect BCBC at H,LH, L and DD, respectively. Show that HAL=DAL\angle HAL=\angle DAL if and only if BAC=90\angle BAC=90^{\circ}.