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prove equal angles starting with an obtuse triangle

Source: Mexican Mathematical Olympiad 2000 OMM P6

July 28, 2018
geometryequal angles

Problem Statement

Let ABCABC be a triangle with B>90o\angle B > 90^o such that there is a point HH on side ACAC with AH=BHAH = BH and BH perpendicular to BCBC. Let DD and EE be the midpoints of ABAB and BCBC respectively. A line through HH parallel to ABAB cuts DEDE at FF. Prove that BCF=ACD\angle BCF = \angle ACD.