MathDB
G(n) = n-G(G(n)), G(0) = 0 , G(k) \ge G(k -1) , G(k -1) = G(k) = G(k +1)

Source: Czech And Slovak Mathematical Olympiad, Round III, Category A 1996 p1

February 20, 2020
Sequencealgebrainequalities

Problem Statement

A sequence (Gn)n=0(G_n)_{n=0}^{\infty} satisfies G(0)=0G(0) = 0 and G(n)=nG(G(n1))G(n) = n-G(G(n-1)) for each nNn \in N. Show that (a) G(k)G(k1)G(k) \ge G(k -1) for every kNk \in N; (b) there is no integer kk for which G(k1)=G(k)=G(k+1)G(k -1) = G(k) = G(k +1).