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Indonesia TST
2016 Indonesia TST
3
summation involving sine squared
summation involving sine squared
Source: Indonesia TST 2016 Round 3
March 24, 2024
algebra
trigonometry
Problem Statement
Let
n
n
n
be a positive integer greater than
1
1
1
. Evaluate the following summation:
∑
k
=
0
n
−
1
1
1
+
8
sin
2
(
k
π
n
)
.
\sum_{k=0}^{n-1} \frac{1}{1 + 8 \sin^2 \left( \frac{k \pi}{n} \right)}.
k
=
0
∑
n
−
1
1
+
8
sin
2
(
n
kπ
)
1
.
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