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a + b + c >= \sqrt{\frac13 (a + 2)(b + 2)(c + 2)} when a,b,c>0 and abc=1

Source: Dutch IMO TST 2013 day 1 p5

August 29, 2019
algebrainequalitiesDutch MOHigh school olympiad

Problem Statement

Let a,ba, b, and cc be positive real numbers satisfying abc=1abc = 1. Show that a+b+c13(a+2)(b+2)(c+2)a + b + c \ge \sqrt{\frac13 (a + 2)(b + 2)(c + 2)}