MathDB
easy number theory from iran

Source: Iran third round 2017 number theory , final exam

September 1, 2017
number theorypolynomialalgebra

Problem Statement

For prime number qq the polynomial P(x)P(x) with integer coefficients is said to be factorable if there exist non-constant polynomials fq,gqf_q,g_q with integer coefficients such that all of the coefficients of the polynomial Q(x)=P(x)fq(x)gq(x)Q(x)=P(x)-f_q(x)g_q(x) are dividable by qq ; and we write: P(x)fq(x)gq(x)(modq)P(x)\equiv f_q(x)g_q(x)\pmod{q} For example the polynomials 2x3+2,x2+1,x3+12x^3+2,x^2+1,x^3+1 can be factored modulo 2,3,p2,3,p in the following way:
{X2+1(x+1)(x+1)(mod2)2x3+2(2x1)3(mod3)X3+1(x+1)(x2x+1)\left\{\begin{array}{lll} X^2+1\equiv (x+1)(-x+1)\pmod{2}\\ 2x^3+2\equiv (2x-1)^3\pmod{3}\\ X^3+1\equiv (x+1)(x^2-x+1) \end{array}\right.
Also the polynomial x22x^2-2 is not factorable modulo p=8k±3p=8k\pm 3.
a) Find all prime numbers pp such that the polynomial P(x)P(x) is factorable modulo pp: P(x)=x42x3+3x22x5P(x)=x^4-2x^3+3x^2-2x-5 b) Does there exist irreducible polynomial P(x)P(x) in Z[x]\mathbb{Z}[x] with integer coefficients such that for each prime number pp , it is factorable modulo pp?