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Product formula for three pairs of intersecting circles

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April 19, 2013

Problem Statement

Three circles in the plane, whose interiors have no common point, meet each other at three pairs of points: A1A_1 and A2A_2, B1B_1 and B2B_2, and C1C_1 and C2C_2, where points A2,B2,C2A_2,B_2,C_2 lie inside the triangle A1B1C1A_1B_1C_1. Prove that A1B2B1C2C1A2=A1C2C1B2B1A2.A_1B_2 \cdot B_1C_2 \cdot C_1A_2 = A_1C_2 \cdot C_1B_2 \cdot B_1A_2 .