MathDB
Why MN is parallel to BC?

Source: JBMO 2003, Problem 3

June 10, 2004
geometrycircumcircleangle bisectorJBMO

Problem Statement

Let DD, EE, FF be the midpoints of the arcs BCBC, CACA, ABAB on the circumcircle of a triangle ABCABC not containing the points AA, BB, CC, respectively. Let the line DEDE meets BCBC and CACA at GG and HH, and let MM be the midpoint of the segment GHGH. Let the line FDFD meet BCBC and ABAB at KK and JJ, and let NN be the midpoint of the segment KJKJ. a) Find the angles of triangle DMNDMN; b) Prove that if PP is the point of intersection of the lines ADAD and EFEF, then the circumcenter of triangle DMNDMN lies on the circumcircle of triangle PMNPMN.