MathDB
ASU 051 All Russian MO 1964 10.2 a-k^n is divisible by b-k

Source:

June 18, 2019
number theory

Problem Statement

Given natural a,b,na,b,n. It is known, that for every natural kk (kbk\ne b) the number akna-k^n is divisible by bkb-k. Prove that a=bna=b^n