MathDB
M/m >= \sqrt3 for 6 houses with min /max distances 2007 Portugal p6

Source:

October 13, 2020
geometryminmaxdistance

Problem Statement

In a village, the maximum distance between two houses is MM and the minimum distance is mm. Prove that if the village has 66 houses, then Mm≥3\frac{M}{m} \ge \sqrt3.
Back to ProblemsView on AoPS