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m_1m_2...m_n divisible by 2^n (Chile NMO 2000 P5)

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December 4, 2021
power of 2dividesdivisiblenumber theory

Problem Statement

Let nn be a positive number. Prove that there exists an integer N=m1m2...mnN =\overline{m_1m_2...m_n} with mi{1,2}m_i \in \{1, 2\} which is divisible by 2n2^n.