MathDB
<TSC=<BAC wanted, parallelogram, circumcircle (2020 Kyiv City MO Round2 11.2)

Source:

September 21, 2020
geometryparallelogramcircumcircleequal angles

Problem Statement

A point PP was chosen on the smaller arc BCBC of the circumcircle of the acute-angled triangle ABCABC. Points RR and SS on the sidesAB AB and ACAC are respectively selected so that CPRSCPRS is a parallelogram. Point TT on the arc ACAC of the circumscribed circle of ABC\vartriangle ABC such that BTCPBT \parallel CP. Prove that TSC=BAC\angle TSC = \angle BAC.
(Anton Trygub)