MathDB
kn = 1+2+...+n (mod 10^100)

Source: 239 2013 S2

August 7, 2020
number theory

Problem Statement

For some 9999-digit number kk, there exist two different 100100-digit numbers nn such that the sum of all natural numbers from 11 to nn ends in the same 100100 digits as the number knkn, but is not equal to it. Prove that kāˆ’3k-3 is divisible by 55.