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Min and Max values of PD+PE+PF of cevians

Source: Czech-Polish-Slovak 2002 Q2

April 28, 2013
geometryinequalitiesgeometry unsolved

Problem Statement

A triangle ABCABC has sides BC=a,CA=b,AB=cBC = a, CA = b, AB = c with a<b<ca < b < c and area SS. Determine the largest number uu and the least number vv such that, for every point PP inside ABC\triangle ABC, the inequality uPD+PE+PFvu \le PD + PE + PF \le v holds, where D,E,FD,E, F are the intersection points of AP,BP,CPAP,BP,CP with the opposite sides.