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f(2018) =? f has period 5, f(x)=x^2 when x \in [-2,3]

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October 1, 2021
algebrafunctions

Problem Statement

Consider a function f:R→Rf: R \to R that fulfills the following two properties: ff is periodic of period 55 (that is, for all x∈Rx\in R, f(x+5)=f(x)f (x + 5) = f (x)), and by restricting ff to the interval [−2,3][-2,3], ff coincides to x2x^2. Determine the value of f(2018).f(2018).
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